1768-merge-strings-alternately

1768. Merge Strings Alternately (Easy) (https://leetcode.com/problems/merge-strings-alternately/)

You are given two strings word1 and word2. Merge the strings by adding letters in alternating order, starting with word1. If a string is longer than the other, append the additional letters onto the end of the merged string. Return the merged string. Constraints: 1 <= word1.length, word2.length <= 100 word1 and word2 consist of lowercase English letters.

function mergeAlternately(word1: string, word2: string): string {
  const result: string[] = []
  for (let i = 0; i < Math.max(word1.length, word2.length); i++) {
    if (i < word1.length)
      result.push(word1[i])
    if (i < word2.length)
      result.push(word2[i])
  }
  return result.join('')
}
 
// Local check:
console.log(mergeAlternately('abc', 'pqr'))
console.log(mergeAlternately('ab', 'pqrs'))
console.log(mergeAlternately('abcd', 'pq'))

Example 1:
 
    Input: word1 = "abc", word2 = "pqr"
    Output: "apbqcr"
    Explanation: The merged string will be merged as so:
      word1:  a   b   c
      word2:    p   q   r
      merged: a p b q c r
 
  Example 2:
 
    Input: word1 = "ab", word2 = "pqrs"
    Output: "apbqrs"
    Explanation: Notice that as word2 is longer, "rs" is appended to the end.
      word1:  a   b
      word2:    p   q   r   s
      merged: a p b q   r   s
 
  Example 3:
 
    Input: word1 = "abcd", word2 = "pq"
    Output: "apbqcd"
    Explanation: Notice that as word1 is longer, "cd" is appended to the end.
      word1:  a   b   c   d
      word2:    p   q
      merged: a p b q c   d

two-pointers\n151-reverse-words-in-a-string\n345-reverse-vowels-of-a-string